∫ ℝ n | u ( x ) | 2 ln | u ( x ) | d μ n ( x ) ≤ 1 2 ‖ ∇ u ‖ 2 2 + ‖ u ‖ 2 2 ln ‖ u ‖ 2
Z = Z1 N N! This implies for the free energy F = -k T ln(Z)